Jawab:
Penjelasan dengan langkah-langkah:
2) [tex]\sf lim_{x\to 2}\ f(x)[/tex]
[tex]\sf = \sf lim_{x\to 2}\ 1 -4x[/tex]= f(2) = 1 - 4(2)
= 1- 8= - 7
3) [tex]\sf lim_{x\to -2}\dfrac{x-4}{x+3}[/tex]
[tex]\sf =\dfrac{-2-4}{-2+3}= \dfrac{-6}{1} = - 6[/tex]
4) [tex]\sf lim_{x\to 1} \dfrac{x^2 +7}{x^2+ 1}[/tex]
[tex]\sf = \dfrac{1^2 +7}{1^2+ 1} = \dfrac{1+7}{1+ 1}= \dfrac{8}{2} = 4[/tex]
5) [tex]\sf lim_{x\to 3}\dfrac{x-3}{x^2 -x - 2}[/tex]
[tex]\sf =\dfrac{3-3}{3^2 -3 - 2}[/tex]
[tex]\sf =\dfrac{0}{4}= 0[/tex]