Bahasa Inggris kls 8​

Setarakan reaksi dibawah ini!

C2H6(g) + O2 (g) ----> CO2(g) + H2O2(g)

Persamaan reaksi menjadi:

C2H6(g) + 5O2 (g) ----> 2CO2(g) + 3H2O2(g)

Penjelasan dengan langkah-langkah:

Diketahui:

C2H6(g) + O2 (g) ----> CO2(g) + H2O2(g)

Ditanya:

Setarakan reaksi kimia tersebut!

Jawab:

aC2H6(g) + bO2 (g) ----> cCO2(g) + dH2O2(g)

2a = c

6a = 2d

2b = 2c + 2d

Misal a = 1

2a = c

2 x 1 = c = 2

6a = 2d

3a = d

3 x 1 = d

d = 3

2b = 2c + 2d

2b = 2 x 2 + 2 x 3

2b = 4 + 6

b = 5

Persamaan reaksi menjadi:

C2H6(g) + 5O2 (g) ----> 2CO2(g) + 3H2O2(g)

Pelajari lebih lanjut

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⬛⬛=persegi panjang

Jawaban:

k ⬛⬛=2×(p+l)

=2×(5+2)

=2×7

=14

k⚫=π×d

=3,14×5

=15,7

k gabungan=(k⚫)+(k⬛⬛)

=15,7+14

=19,7

L ⬛⬛ = p×l

= 5×2

= 10

L ⚫ = π×r×r r=d:2

= 3,14×2,5×2,5 =2,5

= 19,625

L gabungan = ( L ⬛⬛ ) + (L ⚫)

=10+19,625

=29,625

MAtriks Ordo 3x3Determinankofaktor

Penjelasan dengan langkah-langkah:

[tex]\sf A =\left[\begin{array}{ccc}3&-2&0\\4&1&5\\-1&3&2\end{array}\right][/tex]

det A = |A|

[tex]\sf |A |=\left |\begin{array}{ccc}3&-2&0\\4&1&5\\-1&3&2\end{array}\right|[/tex]

[tex]\sf |A| = 3(2 -15) - 4(- 4-0) - 1 (-10 -0)[/tex]

[tex]\sf |A| = 3(-13) - 4(- 4) - 1 (-10)[/tex]

[tex]\sf |A| = - 39 + 16 + 10 = -13[/tex]

Jawaban:

a. 1/5 = 5^-1

b. 1/16 = 16^-1

c. 1/8 = 8^-1

d. 1/2 = 2^-1

semoga membantu

[tex] \mathbb{ \color{aqua}{ \underbrace{JAWABAN}}}[/tex]

[tex] \begin{aligned}&& \begin{aligned} &\bf{a. \: } \boxed{ \bf{ {5}^{ - 1} }} \\ & \bf{b. \: } \boxed{ \bf{ {2}^{ - 4} }} \\ &\bf{c. \:} \boxed{ \bf{ {2}^{ - 3} }} \\ & \bf{d. \: } \boxed{ \bf{ {2}^{ - 1} }} \end{aligned} \end{aligned}[/tex]

[tex] \mathbb{ \color{orange}{ \underbrace{PENYELESAIAN}}}[/tex]

[tex] \begin{aligned}& \begin{aligned} \small{ \bf{ \blue{Gunakan \: sifat \: eksponen \: berikut : }}} \end{aligned} \\ &\boxed{ \: \begin{aligned} \tt{ {a}^{ - n} = \frac{1}{ {a}^{n} } } \end{aligned} \: } \end{aligned} \\ \\ [/tex]

[tex] \boxed{ \: \begin{aligned} \tt{ \frac{1}{5} } &= \tt{ \frac{1}{ {5}^{1} } } \\ &= \red{ \boxed{ \bf{ \pink{ {5}^{ - 1} }}}} \end{aligned} \: } \\ \\ [/tex]

[tex] \boxed{ \: \begin{aligned} \tt{ \frac{1}{16} } &= \tt{ \frac{1}{ {2}^{4} } } \\ &= \red{ \boxed{ \bf{ \pink{ {2}^{ - 4} }}}} \end{aligned} \: } \\ \\ [/tex]

[tex] \boxed{ \: \begin{aligned} \tt{ \frac{1}{8} } &= \tt{ \frac{1}{ {2}^{3} } } \\ &= \red{ \boxed{ \bf{ \pink{ {2}^{ - 3} }}}} \end{aligned} \: } \\ \\ [/tex]

[tex] \boxed{ \: \begin{aligned} \tt{ \frac{1}{2} } &= \tt{ \frac{1}{ {2}^{1}} } \\ &= \red{ \boxed{ \bf{ \pink{ {2}^{ - 1} }}}} \end{aligned} \: }[/tex]

[tex] \colorbox{ff0000}{} \colorbox{ff4000}{}\colorbox{ff8000}{}\colorbox{ffc000}{}\colorbox{ffff00}{}\colorbox{c0ff00}{}\colorbox{80ff00}{}\colorbox{40ff00}{}\colorbox{00ff00}{}\colorbox{00ff40}{}\colorbox{00ff80}{}\colorbox{00ffc0}{}\colorbox{00ffff}{}\colorbox{00c0ff}{}\colorbox{0080ff}{}\colorbox{0040ff}{}\colorbox{0000ff}{}\colorbox{4000ff}{}\colorbox{8000ff}{}\colorbox{c000ff}{}\colorbox{ff00ff}{}\colorbox{ff00c0}{}\colorbox{ff00a0}{}\colorbox{ff0080}{}\colorbox{ff0040}{} [/tex]