Sebutkan 4 macam norma berdasarkan kekuatan Pebgikatnya!​

Jawaban singkat:

Penjelasan tambahan:

Mengubah bilangan desimal (basis 10) ke biner (basis 2):

- bagi bilangan desimal dg angka 2

- tulis hasilnya & sisa baginya dg urut (dari atas ke bawah)

- hentikan pembagian bila hasilnya 1

- penulisan konversi: dari bawah (hasil) ke atas (sisanya)

Perhitungannya bisa dilihat di lampiran.

1.

Diketahui:

q1 = 12×10⁻³ C

q2 = 15×10⁻⁵ C

Jarak (r) = 500 cm = 5 m

K = 9*10⁹ Nm²/C²

Ditanya:

Gaya yang terjadi (F)

Jawab:

F = k x q1 x q2 / r²

= 9*10⁹ x 12×10⁻³ x 15×10⁻⁵ / 5²

= 9*10⁹ x 12×10⁻³ x 15×10⁻⁵ / 25

= 1620*10¹ / 25

= 64,8*10¹

= 648 N

2.

Diketahui:

q = 1,6×10⁻¹⁹ C

F = 3,2×10⁻¹⁴ N

Ditanya:

Kuat medan listrik (E)

Jawab:

E = F / q

E = 3,2×10⁻¹⁴ / 1,6×10⁻¹⁹

E = 2×10⁵ newton per coulomb

3.

Diketahui:

q1 = 20 C

q2 = 40 C

Jarak (r) = 20m

K = 9*10⁹ Nm²/C²

Ditanya:

Gaya yang terjadi (F)

Jawab:

F = k x q1 x q2 / r²

= 9*10⁹ x 20 x 40 / 20²

= 9*10⁹ x 20 x 40 / 400

= 7200*10⁹ / 400

= 18*10⁹ N

[tex]3 \frac{3}{6} + \frac{2}{3} - 1 \frac{3}{5} = 3 \frac{1}{2} + \frac{2}{3} - 1 \frac{3}{5} = \frac{7}{2} + \frac{2}{3} - \frac{8}{5} = \frac{105 + 20 - 48}{30} = \frac{77}{30} [/tex]

●》2 17/30

--

[tex] \\ \\ \\ \\ \\ [/tex]

[tex] 3 \frac{3}{6} + \frac{2}{3} - 1 \frac{3}{5} \\ \\ = \frac{21}{6} + \frac{2}{3} - \frac{8}{5} \\ \\ = \frac{7}{2} + \frac{2}{3} - \frac{8}{5} \: \: \\ \\ = \frac{21}{6} + \frac{4}{6} - \frac{8}{5} \\ \\ = \frac{25}{6} - \frac{8}{5} \: \: \: \: \: \: \: \: \: \: \\ \\ = \frac{125}{30} - \frac{48}{30} \: \: \: \: \: \\ \\ = \frac{77}{30} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ = 2 \frac{17}{30} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

[tex] \\ \\ \\ \\ \\ [/tex]

--

Jawaban:

31/12 atau 2 7/12

Penjelasan:

3 3/4 - 1 1/6

15/4 - 7/6

90-28/24

62/24

31/12

[tex] \mathbb{ \color{aqua}{ \underbrace{JAWABAN}}}[/tex]

[tex] \boxed{ \bf{ \: 2 \frac{7}{12} \: }}[/tex]

[tex] \mathbb{ \color{orange}{ \underbrace{PENYELESAIAN}}}[/tex]

[tex] \boxed{ \: \begin{aligned}& \tt{3 \frac{3}{4} - 1 \frac{1}{6} } \\ & \tt{= (3 - 1) + \left( \frac{3}{4} - \frac{1}{6} \right)} \blue{ \Rightarrow{ \tiny{ \boxed{ \sf{ \purple{samakan \: penyebutnya}}}}}}\\ & \tt{= 2 + \left( \frac{9}{12} - \frac{2}{12} \right)}\\ & \tt{= 2 + \frac{7}{12} }\\ & \tt{= \red{ \boxed{ \pink{ \bf{2 \frac{7}{12} }}}}} \end{aligned} \: }[/tex]

[tex] \\ \\ \huge \color{lightgreen} \xrightarrow {\bf cara \: lain \: : } \\ \\ [/tex]

[tex] \boxed{ \: \begin{aligned}& \tt{3 \frac{3}{4} - 1 \frac{1}{6} }\blue{ \Rightarrow{ \tiny{ \boxed{ \sf{ \purple{ubah \: menjadi \: pecahan \: biasa}}}}}} \\ & \tt{= \frac{15}{4} - \frac{7}{6} } \blue{ \Rightarrow{ \tiny{ \boxed{ \sf{ \purple{samakan \: penyebutnya}}}}}}\\ & \tt{= \frac{45}{12} - \frac{14}{12} }\\ & \tt{= \frac{31}{12} }\\ & \tt{= \red{ \boxed{ \pink{ \bf{2 \frac{7}{12} }}}}} \end{aligned} \: }[/tex]

[tex] \mathbb{ \color{red}{ \underbrace{KESIMPULAN}}}[/tex]

Jadi, hasil dari [tex] \bf{3 \frac{3}{4} - 1 \frac{1}{6} } [/tex] adalah [tex] \bf{ \pink{2 \frac{7}{12} }} [/tex]

[tex] \colorbox{ff0000}{} \colorbox{ff4000}{}\colorbox{ff8000}{}\colorbox{ffc000}{}\colorbox{ffff00}{}\colorbox{c0ff00}{}\colorbox{80ff00}{}\colorbox{40ff00}{}\colorbox{00ff00}{}\colorbox{00ff40}{}\colorbox{00ff80}{}\colorbox{00ffc0}{}\colorbox{00ffff}{}\colorbox{00c0ff}{}\colorbox{0080ff}{}\colorbox{0040ff}{}\colorbox{0000ff}{}\colorbox{4000ff}{}\colorbox{8000ff}{}\colorbox{c000ff}{}\colorbox{ff00ff}{}\colorbox{ff00c0}{}\colorbox{ff00a0}{}\colorbox{ff0080}{}\colorbox{ff0040}{} [/tex]