Bidang studi:
MatematikaPenulis:
micah16Dibuat:
1 tahun lalu(B). [tex]31 - 8 \sqrt{15} [/tex]
PEMBAHASAN :
[tex]\frac{4 - \sqrt{15}}{4 + \sqrt{15}} = \frac{4 - \sqrt{15}}{4 + \sqrt{15}} \times \frac{4 - \sqrt{15}}{4 - \sqrt{15}} = \frac{(4 - \sqrt{15})(4 - \sqrt{15})}{(4 + \sqrt{15})(4 - \sqrt{15})} [/tex]
[tex]= \frac{16 - 4 \sqrt{15} - 4 \sqrt{15} + \sqrt{225}}{16 - 4 \sqrt{15} + 4 \sqrt{15} - \sqrt{225}} [/tex]
[tex]= \frac{16 - (4 + 4) \sqrt{15} + 15}{16 - \sqrt{225}} [/tex]
[tex]= \frac{16 + 15 - 8 \sqrt{5}}{16 - 15} = \frac{31 - 8 \sqrt{5}}{1} = 31 - 8 \sqrt{15} [/tex]
Penulis:
smokeyqiwg
Nilai jawaban:
10