Penjelasan dengan langkah-langkah:
fogoh(x)
= fog(h(x))
[tex] = fog(3 {x}^{2} )[/tex]
[tex] = f( \frac{6(3 {x}^{2}) + 6 }{6} )[/tex]
[tex] = f(3 {x}^{2} + 1)[/tex]
[tex] = \frac{4(3 {x}^{2} + 1) + 3 }{2(3 {x}^{2} + 1) - 7} [/tex]
[tex] = \frac{12 {x}^{2} + 7 }{6 {x}^{2} - 5 } [/tex]
[tex]y= \frac{12 {x}^{2} + 7 }{6 {x}^{2} - 5 } [/tex]
[tex]6 {x}^{2} y - 5y = 12 {x}^{2} + 7[/tex]
[tex]6 {x}^{2} y - 12 {x}^{2} = 5y + 7[/tex]
[tex] {x}^{2} (6y - 12) = 5y + 7[/tex]
[tex] {x}^{2} = \frac{ 5y + 7}{6y - 12} [/tex]
[tex]x = \sqrt{\frac{ 5y + 7}{6y - 12} }[/tex]
[tex] {fogoh}^{ - 1} (x) = \sqrt{\frac{ 5x + 7}{6x - 12} }[/tex]
[tex] {fogoh}^{ - 1} (3) = \sqrt{\frac{ 5(3) + 7}{6(3) - 12} }[/tex]
[tex] = \sqrt{ \frac{11}{3} } [/tex]
[tex] = \frac{1}{3} \sqrt{33} [/tex]