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Bidang studi:
Matematika
Penulis:
marcelino
Dibuat:
1 tahun lalu

Jawaban 2

Nomor 11

[tex] \frac{6}{2 - \sqrt{3} } \\ \\ = \frac{6}{2 - \sqrt{3} } \times \frac{2 + \sqrt{3} }{2 + \sqrt{3} } \\ \\ = \frac{6(2 + \sqrt{3}) }{4 + 2 \sqrt{3} - 2 \sqrt{3} - 3} \\ \\ = \frac{12 + 6 \sqrt{3} }{4 - 3} \\ \\ = \frac{12 + 6 \sqrt{3} }{1} \\ \\ = \bold{12 + 6 \sqrt{3} }[/tex]

[tex] \\ [/tex]

Nomor 12

[tex] {3}^{0} \times {4}^{0} + {2}^{1} - {5}^{0} \\ = 1\times 1 + 2 - 1 \\ = 1 + 2 - 1 \\ = 3 - 1 \\ = \bold2[/tex]

[tex] \\ [/tex]

Nomor 13

[tex] \frac{ { ({2}^{5} )}^{3} }{8} \times 16 \\ \\ = \frac{ {2}^{15} }{ {2}^{3} } \times {2}^{4} \\ \\ = {2}^{15 - 3 + 4} \\ \\ = {2}^{12 + 4} \\ \\ = \bold{ {2}^{16} }[/tex]

[tex] \\ [/tex]

Nomor 14

[tex] \left( \frac{2}{3} \right)^{3} \div \left( \frac{3}{2} \right)^{2} \\ \\ = \frac{ {2}^{3} }{ {3}^{3} } \div \frac{ {3}^{2} }{ {2}^{2} } \\ \\ = \frac{ {2}^{3} }{ {3}^{3} } \times \frac{ {3}^{2} }{ {2}^{2} } \\ \\ = ( {2}^{3 - 2}) \times ( {3}^{2 - 3} ) \\ \\ = {2}^{1} \times {3}^{ - 1} \\ \\ = 2 \times \frac{1}{3} \\ \\ = \bold{ \frac{2}{3} }[/tex]

[tex] \\ [/tex]

Nomor 15

[tex] {2}^{6} = 8 \times {2}^{n} \\ {2}^{6} = {2}^{3} \times {2}^{n} \\ { \not2}^{6} = { \not2}^{3 + n} \\ 6 = 3 + n \\ n = 6 - 3 \\ \bold{n = 3}[/tex]

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