Bidang studi:
MatematikaPenulis:
elsieDibuat:
1 tahun lalux = 0
pembahasan :
f (⅓x-1)=x²-1
f(y) = x²-1
y = ⅓x - 1
⅓x = y + 1
x = 3y + 3
x² - 1 = (3y + 3)² - 1
= 9y²+18y + 9 - 1
= 9y² + 18y + 8
f(y) = 9y² + 18y + 8
f(x) = (-1)
f(y) = (-1)
9y² + 18y + 8 = -1
9y² + 18y + 9 = 0
y² + 2y + 1 = 0
(y +1)² = 0
y = -1
y = ⅓x - 1
-1 = ⅓x - 1
⅓x = 0
x = 0
Penulis:
cadencekibs
Nilai jawaban:
1