fungsi kuadrat f (x) = -2 x² + 4 x -5tentukan sumbu simetri, nilai ekstrim, dan koordinat titik puncaknya

Bidang studi:
Matematika
Penulis:
knucklebutt
Dibuat:
1 tahun lalu

Jawaban 1

PErsamaan Kuadrat

Penjelasan dengan langkah-langkah:

Fungsi kuadrat f (x) = -2 x² + 4 x -5tentukan sumbu simetri, nilai ekstrim, dan koordinat titik puncaknya

f(x) = - 2x² + 4x - 5a= - 2 , b = 4 , c = =5

a) sumbu simetris xp = -b/2axp = -4/2(-2) = -4/-4 = 1

b) nilai ekstrim yp = f(x)yp = f(1)yp = -2(1)² +4(1) - 5yp = -2 + 4 - 5yp= - 3

c) titik puncak P (xp,yp)P(1, - 3)

Penulis:

alexusmoore
Nilai jawaban:
4

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fungsi kuadrat f (x) = -2 x² + 4 x -5tentukan sumbu simetri, nilai ekstrim, dan koordinat titik puncaknya​

Jawaban 1

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fungsi kuadrat f (x) = -2 x² + 4 x -5tentukan sumbu simetri, nilai ekstrim, dan koordinat titik puncaknya