hitunglah bilangan eksponen x−1 − y−2 jika x = −4 dan y = 2sama caranya kak​

Jawaban:

2x² - 5x - 3 = 0

(2x + 1) (x - 3) = 0

x = -1/2 atau x = 3

.....

x1 + x2 = -b/a = -(-4)/2 = 2

Jawab:

Penjelasan dengan langkah-langkah:

1. Tentukan akar-akar persamaan kuadrat dari

2x² – 5x – 3 = 02x² + x  - 6x - 3= 0(2x²+ x) + (-6x- 3) =0x(2x +1) - 3 (2x +1)  =0(x - 3)(2x + 1) = 0x-  3 =0  atau  2x + 1 = 0x=  3   atau x = - 1/2

2. Persamaan kuadrat 2x²–. 4x + 8 = 0 mempunyai akar-akar X1 dan X2. Jumlah akar-akarnya adalah

2x²–. 4x + 8 = 0a = 2 , b = - 4, c = 8x1 + x2 = - b/ax1 +x2= - (-4)/2x1 +x2=  4/2x1 + x2= 2

Jawaban:

25% + 1,5 - 1

25/100 + 15/10 - 10/10

1/4 + 3/2 - 10/10

5/20 + 30/20 - 20/20

15/20 = 3/2 = 1 1/2

[tex] \frac{25}{100 } + \frac{15}{10} - \frac{1}{1} \\ = \frac{25 + 150 - 100}{100} = \frac{75}{100} = \frac{3}{4} [/tex]

#Maaf kalau salah

Penjelasan dengan langkah-langkah:

f(x) = 1 × 2 + 3 × 4 - 5 + x

f(3) = 1 × 2 + 3 × 4 - 5 + 3

f(3) = (1 × 2) + (3 × 4) - 5 + 3

f(3) = 2 + 12 - 5 + 3

f(3) = 14 - 5 + 3

f(3) = 12

f(x) = 1 × 2 + 3 × 4 - 5 + x

f(4) = 1 × 2 + 3 × 4 - 5 + 4

f(4) = (1 × 2) + (3 × 4) - 5 + 4

f(4) = 2 + 12 - 5 + 4

f(4) = 14 - 5 + 4

f(4) = 13

f(x) = 1 × 2 + 3 × 4 - 5 + x

f(5) = 1 × 2 + 3 × 4 - 5 + 5

f(5) = (1 × 2) + (3 × 4) - 5 + 5

f(5) = 2 + 12 - 5 + 5

f(5) = 14 - 5 + 5

f(5) = 14

Penjelasan dengan langkah-langkah:

f(x) = 1 × 2 + 3 × 4 - 5 + x

f(3) = 1 × 2 + 3 × 4 - 5 + 3

f(3) = 2 + 12 - 5 + 3

f(3) = 14 - 5 + 3

f(3) = 9 + 3

f(x) = 1 × 2 + 3 × 4 - 5 + x

f(4) = 1 × 2 + 3 × 4 - 5 + 4

f(4) = 2 + 12 - 5 + 4

f(4) = 14 - 5 + 4

f(4) = 9 + 4

f(x) = 1 × 2 + 3 × 4 - 5 + x

f(5) = 1 × 2 + 3 × 4 - 5 + 5

f(5) = 2 + 12 - 5 + 5

f(5) = 14 - 5 + 5

f(5) = 9 + 5

Jawaban:

pinter

Penjelasan:

bek bek bek bek bek bek bek bek bek cemas kau dek dek