Jawab:
Penjelasan dengan langkah-langkah:
(1) 6ˣ²⁻⁶ˣ⁺⁸ = 5ˣ²⁻⁶ˣ⁺⁸ 6⁰ = 5⁰x² -6x +8 =0(x - 2)(x - 4) =0x= 2 atau x = 4
[tex]\sf (2). \left(\dfrac{1}{4}\right)^{x+1} = \sqrt[3]{8^{2x-1}}[/tex]
[tex]\sf \left(2^{-2})^{x+1} = (2^3)^{\frac{2x-1}{3}}[/tex]
-2(x + 1) = 3(2x -1)/3-2x - 2= 2x - 1-2x -2x = - 1 + 2-4x = 1x =- 1/4
nilai dari 81ˣ=
[tex]81^{x} = (3^4)^{-\frac{1}{4} } = 3^{-1} = \frac{1}{3}[/tex]
(3) 9 .3ˣ + 9ˣ⁺¹ = 910
9. 3ˣ + 9. 9ˣ = 9109. 3ˣ + 9. (3ˣ)² = 910
3ˣ + (3ˣ)² = 103ˣ= aa + a² = 10a² + a - 10 =0(a + 10)(a - 1)=0a = -10 (tm) atau a= 1a= 1 ---> 3ˣ = 13ˣ = 3⁰x= 0