Jawab:a. AB = (-9, 6, -2)
BA = (9, -6, 2)
b. AB = (-5, -3, 9)
BA = (5, 3, -9)
Pendahuluan:
Jenis-jenis vektor:
Contoh: A = [tex]\left[\begin{array}{ccc}4\\-2\\3\end{array}\right][/tex]
Contoh: A = (4, -2, 3)
Contoh: A = 4i -2j+3
Rumus:
AB = B - A
= ((b1-a1), (b2-a2), (b3-a3))
Penjelasan dengan langkah-langkah:a. A = (4, -2, 3) dan B = (-5, 4, 1)
AB = B - A
= (-5, 4, 1) - (4, -2, 3)
= ((-5-4), (4-(-2)), (1-3))
= (-9, 6, -2)
BA = A - B
= (4, -2, 3) - (-5, 4, 1)
= ((4-(-5)), (-2-4), (3-1))
= (9, -6, 2)
Cara lain mencari BA jika AB sudah diketahui:
BA = -1 × AB
= -1 × (-9, 6, -2)
= (9, -6, 2)
b. A = (3, 4, -5) dan B = (-2, 1, 4)
AB = B - A
= (-2, 1, 4) - (3, 4, -5)
= ((-2-3), (1-4), (4-(-5)))
= (-5, -3, 9)
BA = A - B
= (3, 4, -5) - (-2, 1, 4)
= ((3-(-2)), (4-1), (-5-4))
= (5, 3, -9)
Cara lain mencari BA jika AB sudah diketahui:
BA = -1 × AB
= -1 × (-5, -3, 9)
= (5, 3, -9)
Semoga membantu! Apresiasi kalian sangat berharga untuk saya :)
Feel free to ask if there's something you don't understand from my explanation :)