Penjelasan dengan langkah-langkah:
1.
[tex] { ({2}^{3}) }^{4} . {( {2}^{3} )}^{ - 5} = {2}^{12} . {2}^{ - 15} = {2}^{12 - 15} = {2}^{ - 3} = \frac{1}{8} [/tex]
2.
[tex] {5}^{3x - 2} = {25}^{2x + 1} \\ {5}^{3x - 2} = {5}^{2(2x + 1)} = \\ 3x - 2 = 2(2x + 1) \\ 3x - 2 = 4x + 2 \\ 3x - 4x = 2 + 2 \\ - x = 4 \\ x = - 4[/tex]
3.
[tex]4 \sqrt{3} + 3 \sqrt{12} - \sqrt{27} = 4 \sqrt{3} + 3 \sqrt{4.3} - \sqrt{9.3} = 4 \sqrt{3} + 3.2 \sqrt{3} - 3 \sqrt{3} = 4 \sqrt{3} + 6 \sqrt{3} - 3 \sqrt{3} = 7 \sqrt{3} [/tex]
4.
[tex] \frac{6}{ \sqrt{8 } + \sqrt{5} } \times \frac{ \sqrt{8} - \sqrt{5} }{ \sqrt{8} - \sqrt{5} } = \frac{6 \sqrt{8} - 6 \sqrt{5} }{8 - 5} = \frac{6 \sqrt{8} - 6 \sqrt{5} }{3} = 2 \sqrt{8} - 2 \sqrt{5} [/tex]
maaf untuk log nya lupa