Materi : Bentuk dan Persamaan kuadrat
x² - 12x - 5 = 0
[ a = 1 , b = -12 , c = -5 ]
x = ( b ± √[ b² - 4ac ] )/2a
x = ( -12 ± √[ {-12}² - 4{1}{-5} ] )/2(1)
x = ( -12 ± √[ 144 + 20 ] )/2
x = ( -12 ± √164 )/2
x = ( -12 ± √[4×41] )/2
x = ( -12 ± 2√41 )/2
x = -6 ± √41
Himpunan Penyelesaian
x = - 6 + √41
x = - 6 - √41
4m² - 20m + 25 = 0
[ a = 4 , b = -20 , c = 25 ]
x = ( b ± √[ b² - 4ac ] )/2a
x = ( -20 ± √[ {-20}² - 4{4}{25} ] )/2(4)
x = ( -20 ± √[ 400 - 400 ] )/8
x = ( -20 ± √0 )/8
x = ( -20 ± 0 )/8
x = ½( -5 ± 0 )
Himpunan Penyelesaian
x = -5/2 atau x = -5/2
Semoga bisa membantu
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